Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
A | 27563 | 1501 | 32 | 46.9063 |
amely | 1799 | 69 | 2 | 34.5000 |
hogy | 17927 | 389 | 12 | 32.4167 |
Nem | 1267 | 76 | 3 | 25.3333 |
Ez | 2010 | 50 | 2 | 25.0000 |
melyek | 525 | 23 | 1 | 23.0000 |
De | 787 | 44 | 2 | 22.0000 |
Így | 453 | 22 | 1 | 22.0000 |
Egy | 1030 | 61 | 3 | 20.3333 |
mert | 1855 | 80 | 4 | 20.0000 |
s | 1205 | 56 | 3 | 18.6667 |
mely | 1017 | 37 | 2 | 18.5000 |
elmúlt | 487 | 36 | 2 | 18.0000 |
Az | 9830 | 539 | 30 | 17.9667 |
de | 4275 | 154 | 9 | 17.1111 |
Itt | 321 | 16 | 1 | 16.0000 |
illetve | 1402 | 16 | 1 | 16.0000 |
valamint | 1518 | 15 | 1 | 15.0000 |
Még | 240 | 15 | 1 | 15.0000 |
amit | 1040 | 44 | 3 | 14.6667 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
lévő | 432 | 2 | 30 | 0.0667 |
tartó | 171 | 1 | 12 | 0.0833 |
számú | 112 | 1 | 11 | 0.0909 |
adó | 143 | 1 | 11 | 0.0909 |
fenn | 82 | 1 | 9 | 0.1111 |
energia | 164 | 1 | 9 | 0.1111 |
mennyiségű | 100 | 1 | 8 | 0.1250 |
méltó | 96 | 1 | 8 | 0.1250 |
időre | 85 | 1 | 8 | 0.1250 |
intézmény | 172 | 1 | 8 | 0.1250 |
megyében | 127 | 2 | 14 | 0.1429 |
utcai | 99 | 1 | 7 | 0.1429 |
külföldi | 212 | 1 | 7 | 0.1429 |
közlekedés | 81 | 1 | 7 | 0.1429 |
rendelkező | 268 | 2 | 14 | 0.1429 |
izgalmas | 101 | 1 | 7 | 0.1429 |
helyezkedik | 90 | 1 | 6 | 0.1667 |
Önkormányzat | 79 | 1 | 6 | 0.1667 |
látom | 70 | 1 | 6 | 0.1667 |
eredményeként | 69 | 1 | 6 | 0.1667 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II